Heat of reaction for `C_(6)H_(12)O_(6(s))+6O_(2(g)) rarr 6CO_(2(g))+6H_(2)O_(v)` at constant pressure is `-651 kcal` at `17^(@)C`. Calculate the heat of reaction at constant volume at `17^(@)C`.
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To calculate the heat of reaction at constant volume (ΔU) from the heat of reaction at constant pressure (ΔH), we can use the relationship derived from the first law of thermodynamics:
\[
\Delta H = \Delta U + \Delta NRT
\]
Where:
- \(\Delta H\) is the heat of reaction at constant pressure.
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