P BAHADUR|Exercise Exercise(8) Statement:Explanation type problems|19 Videos
THERMODYNAMICS
P BAHADUR|Exercise Exercise|232 Videos
Similar Questions
Explore conceptually related problems
The enthalpy change (Delta H) for the reaction N_(2) (g)+3H_(2)(g) rarr 2NH_(3)(g) is -92.38 kJ at 298 K . What is Delta U at 298 K ?
The enthalpy change (Delta H) for the reaction N_(2) (g) + 3 H_(2) (g) rarr 2 NH_(3) (g) is - 92.38 kJ at 298 K . The internal energy change Delta U at 298 K is
For the reaction, N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) , the units of K_(p) are …………
Calculate the entropy change at 298K for the reaction Br_(2)(l) +CI_(2)(g) rarr 2BrCI(g) DeltaH = 29.3 kJ at 298K . The entropies of Br_(2)(l), CI_(2)(g) , and BrCI(g) at the above temperature and 152.3, 223.0 and 239.7 J mol^(-1)K^(-1) respectively.