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The enthalpy change (DeltaH) for the rea...

The enthalpy change `(DeltaH)` for the reaction, `NH_(2(g))+3H_(2(g)) rarr 2NH_(3g)` is `-92.38kJ` at `298K` What is `DeltaU` at `298K ?`

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`N_(2(g))+3H_(2(g))rarr2NH_(3(g))`
`DeltaH=-92.38kJ at 298 K, DeltaU=?`
`DeltaH=DeltaU+DeltanRT`
`Deltan=2-(3+1)=-2`
`:. -92.38xx10^(3)DeltaU+(-2)xx8.314xx298`
`:. DeltaU=-87424J` ltbr. `=-87.425kJ`
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The enthalpy change ( Delta H ) for the reaction N_(2)(g) + 3H_(2)(g) rarr 2NH_(2)(g) is -92.38 kJ at 298 K . What is DeltaU at 298 K ?

The enthalpy change (Delta H) for the reaction N_(2) (g)+3H_(2)(g) rarr 2NH_(3)(g) is -92.38 kJ at 298 K . What is Delta U at 298 K ?

Knowledge Check

  • The enthalpy change (DeltaH) for the reaction, N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g) " is "-92.38 kJ at 298 K. The internal energy change DeltaU at 298 K is

    A
    `-92.38 kJ`
    B
    `-87.42 kJ`
    C
    `-97.34 kJ`
    D
    `-89.9 kJ`

  • The enthalpy change (Delta H) for the reaction N_(2) (g) + 3 H_(2) (g) rarr 2 NH_(3) (g) is - 92.38 kJ at 298 K . The internal energy change Delta U at 298 K is

    A
    `- 92.38 kJ mol^(-)`
    B
    `- 87.42 kJ`
    C
    `- 97.34 kJ`
    D
    `- 89.9 kJ`

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