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DeltaH(f)^(@) for Al(2)O(3) is -1670kJ. ...

`DeltaH_(f)^(@)` for `Al_(2)O_(3)` is `-1670kJ`. Calculate the enthalpy change for the reaction`:4Al+3O_(2) rarr 2Al_(2)O_(3)`.

Text Solution

Verified by Experts

Given`:2Al+(3//2)O_(2) rarr Al_(2)O_(3),DeltaH=-1670kJ` multiplying it by 2,
`4Al+3O_(2) rarr 2Al_(2)O_(3),`
`DeltaH=2xx(-1670)=-3340kJ`
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Knowledge Check

  • Al_(2)O_(3) reacts with

    A
    only water
    B
    only acids
    C
    only alkalis
    D
    both acids and alkalis
  • 27 gm of Al will react completely with: 4Al + 3O_(2) rarr 2Al_(2)O_(3)

    A
    24 gm of `O_(2)`
    B
    0.75 moles of `O_(2)`
    C
    16.8 L of `O_(2)` at 1 atm , 273 K
    D
    0.75 `N_(A)` molecules of `O_(2)`
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    B
    `-462` kJ
    C
    `-1365` kJ
    D
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