The specific heats of iodine vapour and solid are `0.031` and `0.055 cal//g` respectively. If heat of sublimation of iodinde is `24cal//g` at `200^(@)C`, what is its value at `250^(@)C` ?

Explanation

To find the heat of sublimation of iodine at 250°C, we can use the concept of specific heat and the heat of sublimation at a known temperature (200°C). The heat of sublimation changes with temperature, and we can estimate this change using the specific heats of the solid and vapor phases of iodine.

### Step-by-Step Solution:

1. **Identify Given Data**:
- Specific heat of iodine vapor, \( C_{v} = 0.031 \, \text{cal/g°C} \)
- Specific heat of iodine solid, \( C_{s} = 0.055 \, \text{cal/g°C} \)
- Heat of sublimation at 200°C, \( \Delta H_{sub} (200°C) = 24 \, \text{cal/g} \)
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