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A cone lies in a uniform electric field ...

A cone lies in a uniform electric field `E` as shown in figure. The electric flux entering the cone is

A

`EpiR^(2)`

B

`ERh`

C

`(E hR)/(2)`

D

`Eh^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Plane normal to electric field is a triangle with base length `2R` and hight `h`

Area of triangle `A=1/2xx2Rh= Rh`
Electric flux entering the once `=EA= ERh`
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Knowledge Check

  • In figure , a cone lies in a uniform electric field E. Determine the electric flux entering the cone. .

    A
    `(ERh)/2`
    B
    0
    C
    `2ERh`
    D
    `Erh`

  • A conic surface is placed in a uniform electric field E as shown in figure. Such that the field is perpendicular to the surface on the side AB. The base of the cone is of radius R, and the height of the cone is h. The angle of the cone is theta . Find the magnitude of the flux that enters the cone's curved surface from the left side. Do not count the outgoing flux (thetalt45^@) .

    A
    `ER[h cos theta + pi(R//2)sin theta]`
    B
    `ER[h cos theta + piR//2sin theta]`
    C
    `ER[h cos theta + piRsin theta]`
    D
    none of these

  • Find the electric field in region II as shown in figure.

    A
    zero
    B
    `(sigma)/(4piepsilon_(0))`
    C
    `(sigma)/(epsilon_(0))`
    D
    Infinite

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