The inward and outward electric flux for a closed surface unit of `N-m^(2)//C` are respectively `8xx10^(3)` and `4xx10^(3)`. Then the total charge inside the surface is [where `epsilon_(0)=` permittivity constant]

Options

A. `4xx10^(3)C`
B. `-4xx10^(3)C`
C. `((-4xx10^(3)))/(epsilon)C`
D. `-4xx10^(3)epsilon_(0)C`

Answer

D

Explanation

By Gauss's law `varphi=(1)/(epsilon_(0))(Q_(enclosed))`
`implies Q_(enclosed)= varphiepsilon_(0)=(-8xx10^(3)+4xx10^(3))epsilon_(0)`
`=-4xx10^(3)epsilon_(0)` Coulomb.