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A rectangle loop with a sliding connecto...

A rectangle loop with a sliding connector of length `l=1.0 m` is situated in a uniform magnetic field `B=2T` perpendicular to the plane of loop. Resistance of connector is `r=2Omega`. Two resistance of `6Omega` and `3Omega` are connected as shown in figure. the external force required to keep the connector moving with a constant velocity `v=2m//s` is

A

`6N`

B

`4N`

C

`2N`

D

`1N`

Text Solution

Verified by Experts

The correct Answer is:
C

Motional e.m.f. `e=Bvl`
`e=(2)(2)(1)=4V`
thisact as a cell of e.m.f.`E=4V` and internal resistance
`r=2Omega`. The simple circuit can be drawn as follows:
:. Current through the connector
`i=(4)/(2+2)=1A`
magnetic force on cinnector `F_(m)=ilB`
`=(1)(1)(2)`
`=2N("towards left")`
therefore, to keep the connetor moving with a constant velocity a force of `2N` will have to be applied towards right.
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Knowledge Check

  • A rectangular loop with a sliding connector of length l = 1.0 m is situated in a uniform magnetic field B = 2T perpendicular to the plane of loop. Resistance of connector is r = 2 Omega . Two resistances of 6Omega and 3Omega are connected as shown in . The external force required to keep the connetor moving with a constant velocity v = 2 m s^(-1) is

    A
    (a) `6n`
    B
    (b) `4n`
    C
    ( c) `2n`
    D
    (d) `1n`
  • A rectangular loop with a sliding connector of length l=1.0 m is situated in a uniform magnetic field B=2T perpendicular to the plane of loop. Resistance of connector is r=2Omega .Two resistance of 6Omega and 3Omega are connector is r=2Omega . two resistance of 6Omega and 3Omega are connected as shown in figure. the external force required to keep the connector moving with a constant velocity v=2m//s is

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    B
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    C
    `1/55A`
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