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If the de - Broglie wavelengths for a pr...

If the de - Broglie wavelengths for a proton and for an `alpha` - particle is equal , then what is the ratio of velocities for proton and alpha particle?

A

`4 : 1`

B

`2 : 1`

C

`1 : 2`

D

`1 : 4`

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio of velocities for a proton and an alpha particle given that their de Broglie wavelengths are equal, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the de Broglie Wavelength Formula**: The de Broglie wavelength (λ) is given by the formula: \[ \lambda = \frac{h}{p} \] where \( h \) is Planck's constant and \( p \) is the momentum of the particle. 2. **Express Momentum**: The momentum \( p \) can be expressed in terms of mass \( m \) and velocity \( v \): \[ p = mv \] Therefore, the de Broglie wavelength can be rewritten as: \[ \lambda = \frac{h}{mv} \] 3. **Set Up the Equation for Both Particles**: Since the de Broglie wavelengths for the proton and alpha particle are equal, we can write: \[ \lambda_p = \lambda_{\alpha} \] This leads to: \[ \frac{h}{m_p v_p} = \frac{h}{m_{\alpha} v_{\alpha}} \] where \( m_p \) and \( v_p \) are the mass and velocity of the proton, and \( m_{\alpha} \) and \( v_{\alpha} \) are the mass and velocity of the alpha particle. 4. **Cancel Planck's Constant**: Since \( h \) is a constant and appears on both sides, we can cancel it out: \[ \frac{1}{m_p v_p} = \frac{1}{m_{\alpha} v_{\alpha}} \] 5. **Rearrange the Equation**: Rearranging gives us: \[ m_{\alpha} v_{\alpha} = m_p v_p \] 6. **Substitute the Masses**: The mass of a proton \( m_p \) is approximately 1 amu, and the mass of an alpha particle \( m_{\alpha} \) is approximately 4 amu. Substituting these values in: \[ 4 v_{\alpha} = 1 v_p \] 7. **Find the Ratio of Velocities**: Rearranging this gives us the ratio of velocities: \[ \frac{v_p}{v_{\alpha}} = \frac{4}{1} \] Thus, the ratio of the velocities of the proton to the alpha particle is: \[ \frac{v_p}{v_{\alpha}} = 4:1 \] ### Final Answer: The ratio of velocities for the proton and alpha particle is \( 4:1 \).

To solve the problem of finding the ratio of velocities for a proton and an alpha particle given that their de Broglie wavelengths are equal, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the de Broglie Wavelength Formula**: The de Broglie wavelength (λ) is given by the formula: \[ \lambda = \frac{h}{p} ...
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Knowledge Check

  • If the de-Brolie wavelength for a proton and for a alpha -particle are equal, then the ratio of their velocities will be

    A
    `4 : 1`
    B
    `2 : 1`
    C
    `1 : 2`
    D
    `1 : 4`
  • The ratio of deBroglie wavelengths of a proton and an alpha particle of same energy is.

    A
    1
    B
    2
    C
    4
    D
    0.25
  • The de-Broglie wavelength relates to applied voltage for alpha -particles as

    A
    `lambda= 12.3/sqrt(V)`
    B
    `lambda= 0.286/sqrt(V)`
    C
    `lambda= 0.101/sqrt(V)`
    D
    `lambda= 0.856/sqrt(V)`
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