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When two deuterium nuclei fuse together ...

When two deuterium nuclei fuse together to form a tritium nuclei, we get a

A

Neutron

B

Deuteron

C

`alpha-`particle

D

Proton

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `._1 H^2 + ._1 H^2 rarr ._1 H^3 + ._1 H^1`.
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A deuterium reaction that occurs in an experimental fusion reactor is in two stage: (a) Two deuterium (._1^2D) nuclei fuse together to form a tritium nucleus, with a proton as a by product written as D(D,p)T . (b) A tritium nucleus fuses with another deuterium nucleus to form a helium ._2^4He nucleus with neutron as a by - product, written as T (D,n) ._2^4He . Compute (a) the energy released in each of the two stages, (b) the energy released in the combined reaction per deutrium. (c ) What percentage of the mass energy of the initial deuterium is released. Given, {:(._1^2D=2.014102 am u),(._1^3 T=3.016049), (._2^4 He =4.002603 am u),(._1^1 H =1.007825 am u),(._0^1 n =1.00665 am u):} .

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Knowledge Check

  • The binding energy per nucleon of deuterium and helium nuclei are 1.1 MeV and 7.0 MeV respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is

    A
    23.6 MeV
    B
    2.2 MeV
    C
    28.0 MeV
    D
    30.2 MeV

  • When two nuclei (A le 10) fuse together to form a heavier nucleus, the

    A
    binding energy per uncleon increases.
    B
    binding energy per uncleon decreases.
    C
    binding energy per nucleon does not change.
    D
    total binding energy decreases.

  • Two lighter nuclei are fused together to form another nucleus an energy is released in the process because

    A
    binding energy of lighter nucleus is more
    B
    binding energy per nucleon of lighter nucleus is more
    C
    binding energy per nucleon is more for medium nucleus
    D
    energy is always released when two nuclei are combined.

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