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If N(0) is the original mass of the subs...

If `N_(0)` is the original mass of the substance of half - life period `t_(1//2) = 5 year` then the amount of substance left after `15` year is

A

`N_0//8`

B

`N_0//16`

C

`N_0//2`

D

`N_0//4`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `N = N_0 ((1)/(2))^((t)/(T_1//2)) = N_0 ((1)/(2))^((15)/(5)) = (N_0)/(8)`.
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Knowledge Check

  • If N_(0) is the initial mass of a substances with hal ,life t_(1//2)=5 years, then the amount of substance left after 15 years is

    A
    `(N_(0))/8`
    B
    `(N_(0))/16`
    C
    `(N_(0))/2`
    D
    `(N_(0))/4`

  • If halfe-life of a substance is 5 yrs, then the total amount of substance left after 15 years, when initial amount is 64 grams is

    A
    16 grams
    B
    2 grams
    C
    32 grams
    D
    8 grams

  • The half-life period of a order reaction is 15 minutes. The amount of substance left after one hour will be:

    A
    `(1)/(4)` of the original amount
    B
    `(1)/(8)` of the original amount
    C
    `(1)/(16)` of the original amount
    D
    `(1)/(32)` of the original amount

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