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The two equilibrium AB hArr A^(+)+B^(+) ...

The two equilibrium `AB hArr A^(+)+B^(+)` and `AB+B^(-)hArrAB_(2)^(-)` are simultaneously maintained in a solution with equilibrium, constant `K_(1)` and `K_(2)` respectively, The ratio of `A^(+)` to `AB_(2)^(-)` in the solution is:

A

directly prooprtional to theconcentration of `B^(-)`

B

inversely proportional to the concentration of `B^(-)`

C

directly proportional to the square of the concentration of `B^(-)`

D

inversely proprtional to the square of the concentration of `B^(-)`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(1)=([A^(+)][B^(-)])/([AB])`
`K_(2)= ([AB_(2)^(-)])/([AB][B^(-)])`
`:. (K_(1))/(K_(2))= ([A^(+)][B^(-)]^(2))/([Ab_(2)^(-2)])`
`:. ([A^(+)])/(AB_(2)^(-)]prop(1)/([B^(-)]^(2))`
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