Vapour pressure of `C_(6)H_(6)` and `C_(7)H_(8)` mixture at `50^(circ)C` are given by `P=179X_(B)+92`, where `X_(B)` is mole fraction of `C_(6)H_(6)`. Calculate (in `mm`):
(a) Vapour pressure of pure liquids.
(b) Vapour pressure of liquid mixture obtained by mixing `936g C_(6)H_(6)` and `736g` toluene.
( c) If the vapours are removed and condensed into liquid and again brought to the temperature of `50^(circ)C`, what would be mole fraction of `C_(6)H_(6)` in vapour state ?

Answer

(a) `92 mm`, (b) `199.4 mm`,
( c) `0.815, 0.185, 0.928, 0.072`;