Home
Class 12
CHEMISTRY
A current of 0.5 A is passed through aci...

A current of `0.5 A` is passed through acidulated water for `30` minute. Calculate weight of `H_(2)` and `O_(2)` evolved. Also calculate the volume of `O_(2)` produced at `25^(@)C` and `760` mm of `Hg`, if the gas is :
(a) dry
(b) saturated with water vapour (aqueous tension is `23.0` mm at `25^(@)C`).

Text Solution

Verified by Experts

The correct Answer is:
`H_(2) = 9.33 xx 10^(-3)g`,
`O_(2) = 7.46 xx 10^(-2)g`,
(a) `5.7 xx 10^(-2)` litre, (b) `5.88 xx 10^(-2)` litre;
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    P BAHADUR|Exercise Exercise (7) COMPREHENSION BASED OBJECTIVE PROBLEMS|3 Videos

  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    P BAHADUR|Exercise Exercise 9 Advanced Numerical|12 Videos

  • MOCK TEST PAPER

    P BAHADUR|Exercise Exercise|92 Videos

Similar Questions

Explore conceptually related problems

0.6 g of a gas at 15^(@)C and 745 mm Hg occupies 200cm^(3) . It occupies 182.6cm^(3) in dry state at N.T.P. Calculate the aqueous tension at 15^(@)C.

The surface tension of water at 0^(@) C is 75.5 dyn/cm. Calculate the surface tension of water at 25^(@)C .

Knowledge Check

  • If 0.5 A current is passed through acidified water for 30 minute then determine the volume of O_(2) (g) being produced at 25^(@)C and 760 mm of Hg provided the gas is saturated using water vapour (Given: aqueous tension = 23.0 mm at 25^(@)C ).

    A
    `5.88 xx 10^(-2)L`
    B
    `17.4 xx 10^(-2)L `
    C
    `1.31 xx 10^(-2)L`
    D
    `11.3 xx 10^(-2)L`

  • An elecric current 0.25 ampere was passed through acidified water for two hours, the volume of H_(2) produced at N.T.P is

    A
    20.16 litres
    B
    0.2016litres
    C
    2.016litres
    D
    0.4032 litres.

  • Calculate the volume of O_(2) liberated at STP by passing 5A current for 193 sec through acidicied water.

    A
    56 mL
    B
    112 mL
    C
    158 mL
    D
    965 mL

    • Similar Questions

    Explore conceptually related problems

    When dissolved in dilute H_(2)SO_(4), 0.275 g of metal evolved 119.7 mL of H_(2) at 20^(@)C and 780.4 mm pressure. H_(2) was collected over water. Aqueous tension is 17.4 mm at 20^(@)C . Calculate equivalent weight of metal.

    50 litre of dry N_(2) is passed through 36 g H_(2)O at 27^(@)C . After the passage of the gas, the mass of water was reduced to 34.80 g. Calculate the aqueous tension of water at 27^(@)C .

    38.00 mL of moist nitrogen gas were collected at 27^(@)C and 746.5 mm pressure. Calculate the volume of the gas at 0^(@)C and 760 mm pressure, (Aq. Tension at 27^(@)C is 26.5 mm).

    If 720 litres of a gas were collected over water at 25^(@)C and 720 mm then the volume of the dry gas at the same temperature and pressure is (aq. Tension of water at 25^(@)C = 23.8 mm)

    2 gm of O_(2) at 27^(@)C and 760 mm of Hg pressure has volume "____________" .

    Home
    Profile