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The data given below are for the reactio...

The data given below are for the reaction of `NO` and `Cl_(2)` to from `NOCl` at `295 K`.
`{:([Cl_(2)],[NO],,,"Initial rate" (mol litre^(-1) sec^(-1))),(0.05,0.05,,,1xx10^(-3)),(0.15,0.05,,,3xx10^(-3)),(0.05,0.15,,,9xx10^(-3)):}`

(a) What is the order with respect to `NO` and `Cl_(2)` in the reaction ?
(b) Write the rate expression.
(c) Calculate the rate constant.
(d) Determine the reaction rate when conc. of `Cl_(2)` and `NO` are `0.2` M and `0.4` M respectively.

Text Solution

AI Generated Solution

To solve the problem step by step, we will analyze the given data and find the required information. ### Step 1: Determine the order of the reaction with respect to `NO` and `Cl2`. We have three sets of data: 1. \([Cl_2] = 0.05 \, M, [NO] = 0.05 \, M, \text{Rate} = 1 \times 10^{-3} \, mol \, L^{-1} \, s^{-1}\) 2. \([Cl_2] = 0.15 \, M, [NO] = 0.05 \, M, \text{Rate} = 3 \times 10^{-3} \, mol \, L^{-1} \, s^{-1}\) ...
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