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A 0.05 m cube has its upper face displac...

A `0.05 m` cube has its upper face displaced by `0.2 cm` by a tangential force of `8N`. Calculate the shearing strain, shearing stress and modulus of rigidity of the material of the cube.

Text Solution

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`L=5 cm =5 xx 10^(-2) m, Delta L=0.2 cm =0.2 xx 10^(-2) m`,
`F=8N` ,
Shearing strain `=(Delta L)/(L) = (0.2)/(5) = 0.04`,
Shearing stress = `(F)/(L xx L) = (8)/((5 xx 10^(-2))^(2))`
`= 3200 N//m^(2)`
Modulus of rigidity, `G = ("shearing stress")/("shearing strain") =(3200)/(0.04)`
`=80000 N//m^(2)`
`=8 xx 10^(4)N//m^(2)`.
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