Find the velocity of efflux of water from an oriffice near the bottom of a tank in which pressure is `500 gf//sq` cm above atmosphere.

Explanation

Pressure at orifice,
`P= 500 gf//sq cm`
`= 500/1000 xx 9.8 xx (100)^(2) Nm^(-2)`
`= 500 xx 9.8 Nm^(-2)`
Let h be the depth of orifice below the surface.
As, `P = h rho g`
`:. H=P/(rho g) = (500 xx 98)/(10^(3) xx 9.8) = 5 cm`
The velocity of effux,
`upsilon = sqrt(2gh) = sqrt(2xx9.8xx5) = 9.893 ms^(-1)`.