A man, the surface area of whose skin is `2m^(2)` , is sitting in a room where air temperature is `20^(@)C` if his skin temperature is `28^(@)C` and emissivity of his skin equals 0.97, find the rate at which his body loses heat.

Explanation

To find the rate at which the man's body loses heat, we can use the Stefan-Boltzmann law, which is given by the formula:

\[ P = \epsilon \cdot A \cdot \sigma \cdot (T^4 - T_0^4) \]

Where:
- \( P \) is the power (rate of heat loss) in watts (W),
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