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The volume of an ideal gas is V at press...

The volume of an ideal gas is `V` at pressure `P`. On increasing the pressure by `DeltaP`, change in volume of gas is `DeltaV_(1)`, under isothermal conditions and `DeltaV_(2)` under adiabatic conditions. Which is more and why?

Text Solution

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Under isothermal conditions, `K_(i)=(DeltaP)/(DeltaV_(1)//V)=P`,
and under adiabatic conditions,
`K_(a)= (DeltaP)/(DeltaV_(2)//V)=gammaP`
Dividing, we get, `gamma=(DeltaV_(1))/(DeltaV_(2))`
As `gammagt1, :. DeltaV_(1)gtDeltaV_(2)`
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Knowledge Check

  • Heat given to an ideal gas under isothermal conditions is used

    A
    increasin the temp
    B
    in doing external work
    C
    in increasing the internal energy
    D
    None of these

  • The pressure p and volume V of an ideal gas both increase in a process.

    A
    such a process is not possible.
    B
    The work done by the system is positive.
    C
    The tempreture of the system must increase.
    D
    Heat supplied to the gas is equal to the change in internal energy.

  • Certain amount of heat supplied to an ideal gas under isothermal conditions will result in

    A
    rise in temperature q
    B
    doing external work and a change in temperature
    C
    doing external work
    D
    an increase in the internal energy of the gas

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