The volume of an ideal gas is `V` at pressure `P`. On increasing the pressure by `DeltaP`, change in volume of gas is `DeltaV_(1)`, under isothermal conditions and `DeltaV_(2)` under adiabatic conditions. Which is more and why?

Explanation

Under isothermal conditions, `K_(i)=(DeltaP)/(DeltaV_(1)//V)=P`,
and under adiabatic conditions,
`K_(a)= (DeltaP)/(DeltaV_(2)//V)=gammaP`
Dividing, we get, `gamma=(DeltaV_(1))/(DeltaV_(2))`
As `gammagt1, :. DeltaV_(1)gtDeltaV_(2)`