Calculate the mean free path and the collsion frequency of air molecules, if the number of molecules per `cm^(3) is 3 xx 10^(19)`, the diameter of the molecule is `2 xx 10^(-8) cm` and average molecule speed is `1 km s^(-1)`.

Explanation

To solve the problem of calculating the mean free path and the collision frequency of air molecules, we will follow these steps:

### Step 1: Convert Given Values
- **Number of molecules per cm³**: \( n = 3 \times 10^{19} \, \text{molecules/cm}^3 \)
- **Convert to m³**:
\[ n = 3 \times 10^{19} \, \text{molecules/cm}^3 \times (10^2 \, \text{cm/m})^3 = 3 \times 10^{25} \, \text{molecules/m}^3 \]
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