Home
Class 12
PHYSICS
Find the percent increase in the magneti...

Find the percent increase in the magnetic field `B` when the space within a current- carrying toroid is filled with aluminium. The susceptibility of aluminium is `2.1 xx 10^(-5)`.

Text Solution

Verified by Experts

In the absence of aluminium,
`B_0=mu_0H`.
In the presence of aluminium,
`B=muH=mu_0(1+chi_m)H`
Increase in magnetic field induction
`=B-B_0=mu_0 chi_mH`
Percentage increase `=(B-B_0)/(B_0)xx100`
`=(mu_0chi_mH)/(mu_0H)xx100`
`=2*1xx10^-5xx100=2*1xx10^-3`
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Conceptual Problems (d)|2 Videos
  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Very Short Answer Questions (a)|2 Videos
  • ELECTROSTATICS

    PRADEEP|Exercise ASSERTION-REASON TYPE QUESTIONS|2 Videos
  • OPTICS

    PRADEEP|Exercise Multiple choice questions|1 Videos

Similar Questions

Explore conceptually related problems

Find the per cent increase in the magnetic field B when the space within a current- carrying toroid is filled with aluminiu. The susceptibility of aluminium is 2.1 xx 10^(-5) .

The percentage increase in magnetic field B when the space within a current carrying toroid is filled with aluminum (chi=2.1xx10^(-5)) is

The value of aluminium susceptibility is 2.2xx10^(-5) . The percentage increase in the magnetic field if space within a current carrying toroid is filled with aluminium is (x)/(10^(4)) . Then the values of x is ___________.

The space within a current carrying toroid is filled with aluminium of magnetic suceptibiliuty 2.1 xx10^(-5) what is the percentage increase in the magnetic induction B ?

The space within a current carrying toroid is filled with tungsten of susceptibility 4.6 xx 10^(-5) . The percentage increase in the magnetic field is

An ideal solenoid having 40 turns cm^(-1) has an aluminium core and carries a current of 2.0 A . Calculate the magnetization I developed in the core and the magnetic field B at the centre. The susceptibility chi of aluminium = 2.3 xx 10^(-5) .