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What is the torque acting on a magnet of...

What is the torque acting on a magnet of magnetic moment M held at an angel `theta` with the direction of magnetic field B?

Text Solution

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`tau=MBsintheta`
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Knowledge Check

  • The torque acting on a magnet of magnetic moment 'M' placed in a uniform magnetic field B is

    A
    perpendicular to `vecM," parallel to "vec B`
    B
    parallel to `vecM," perpendicular to " vecB`
    C
    perpendicular to both `vecM and vec B`
    D
    parallel to both `vecM and vecB`.

  • The value of workdone for rotating a magnet of magnetic moment M by an angle theta in external magnetic field H is given by

    A
    `MH cos theta`
    B
    `2 Mhsin^(2) (theta/2)`
    C
    `MH sin theta`
    D
    `MH (-1 sin^(2)theta)`

  • The work done in rotating a magnet of magnetic moment 2A-m^(2) in a magnetic field to opposite direction to the magnetic field, is

    A
    Zero
    B
    `2xx10^(-2)J`
    C
    `10^(-2)J`
    D
    `10J`

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    Two magnets of magnetic moments M and Msqrt3 are joined to form a cross(+) . The combination is suspended freely in a uniform magnetic field . At equilibrium position, the magnet of magnetic moment M makes an angle theta with the field, then theta is

    The torque acting on a magnetic dipole of moment P_(m) when placed in a magnetic field is

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