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A coil of 1 H and 100 Omega resistance h...

A coil of 1 H and `100 Omega` resistance has a peak voltage of `5 sqrt2` volt 50 hz connected across it. Calculate the current through the coil and power absorbed.

Text Solution

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Here, `L = 1 H, R = 1000 Omega, E_(0) = 5 sqrt 2 V, v = 50 hz, I_(v) = ? P = ?`
`X_(L) = omega L = 2 pi v L = 2 pi xx 50 xx 1 = 1000 pi`
`Z = sqrt(R^(2) + X_(L)^(2)) = sqrt(100^(2) + (100 pi)^(2)) = 1.52 xx 10^(-2) A`
`I_(v) = (E_(v))/(Z) = (E_(0))/(sqrt2 (Z)) = (5 sqrt 2)/(sqrt 2 xx 3.3 xx 10^(2)) = 1.52 xx 10^(-2) A`
`P = E_(v) I_(v) cos phi = E_(v) I_(v) (R//Z)`
`P = 5 xx 1.52 xx 10^(-2) xx (100)/(3.3 xx 10^(2)) = 2.29 xx 10^(-2)` watt
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