When an AC voltage of 220 V is applied to the capacitor C

Options

A. the maximum voltage between plates is 220 V
B. the current is in phase with the applied voltage
C. the charge on the plates is in phase with the applied voltage
D. power delivered to the capacitor is zero

Explanation

To solve the problem of determining the peak voltage when an AC voltage of 220 V (Vrms) is applied to a capacitor, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Relationship Between Vrms and Vpeak**:
The root mean square (RMS) voltage (Vrms) is related to the peak voltage (Vpeak) in an AC circuit by the formula:
\[ V_{peak} = V_{rms} \times \sqrt{2} \]

2. **Substitute the Given Value**:
We know that \( V_{rms} = 220 \, V \). Now, we can substitute this value into the formula:
\[ V_{peak} = 220 \, V \times \sqrt{2} \]

3. **Calculate Vpeak**:
To find \( V_{peak} \), we need to calculate \( \sqrt{2} \), which is approximately 1.414. Therefore:
\[ V_{peak} = 220 \, V \times 1.414 \approx 311.08 \, V \]

4. **Final Result**:
The peak voltage when an AC voltage of 220 V is applied to the capacitor is approximately:
\[ V_{peak} \approx 311.08 \, V \]

### Summary:
The peak voltage (Vpeak) when an AC voltage of 220 V (Vrms) is applied to the capacitor is approximately 311.08 V.