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When a capacitor of capacitance C after ...

When a capacitor of capacitance C after charging with a charge Q is connected to inductor of self inductance L, the oscillation of charge takes place with time between the two plates of capacitor. If one plate of capacitor is connected to antenna and other plate is earthed, then em wave are produced, which are sinusoidal variation of electric and magnetic field vectors, perpendicular to each other as well as perpendicular to the direction of propagation of wave. The velocity of these waves depends upon the electric and magnetic properties of the medium. the em wave were produced experimentally by Hertz in 1888 using Hertz Oscillator, which were of wavelength 6m. Jagdish chander bose in 1895 produced these waves which were of wave length 5mm to 25mm and in 1896, G. Marconi established a wireless communication between two stations 50km apart using em waves. In an em wave, the amplitude of electric field is `10Vm^-1`. The frequency of wave is `5xx10^(14)Hz .` the wave is propagating along z-axis.
Sun also sends em wave to earth. which one of em wave out of the visible portion, from sun will be reaching the surface of earth earlier than others:

A

violet waves

B

green waves

C

yellow waves

D

red waves

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine which electromagnetic (EM) wave from the visible spectrum reaches the Earth's surface first. The key points to consider are the properties of EM waves and their propagation through a vacuum. ### Step-by-Step Solution: 1. **Understanding EM Waves**: EM waves consist of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of propagation. The speed of EM waves in a vacuum is constant and is denoted by \( c \) (approximately \( 3 \times 10^8 \) m/s). 2. **Frequency and Wavelength Relationship**: The relationship between the speed \( c \), frequency \( \nu \), and wavelength \( \lambda \) of an EM wave is given by the equation: \[ c = \nu \lambda \] Rearranging this gives: \[ \lambda = \frac{c}{\nu} \] 3. **Visible Spectrum**: The visible spectrum consists of different colors, each with a specific frequency and wavelength. The order of colors from longest wavelength to shortest wavelength is: - Red (longest wavelength) - Orange - Yellow - Green - Blue - Indigo - Violet (shortest wavelength) 4. **Propagation Speed**: All colors of visible light travel at the same speed in a vacuum, which is \( c \). However, the wavelength and frequency differ. 5. **Comparing Wavelengths**: Since red light has the longest wavelength, it will have the lowest frequency compared to the other colors. Conversely, violet light has the shortest wavelength and the highest frequency. 6. **Arrival Time**: Since all EM waves travel at the same speed in a vacuum, the time taken to reach the Earth’s surface is independent of their frequency or wavelength. Therefore, all colors of light from the sun will reach the Earth simultaneously. 7. **Conclusion**: Since all visible light waves travel at the same speed in a vacuum, there is no specific color that will reach the Earth's surface earlier than the others. They all arrive at the same time. ### Final Answer: All colors of visible light from the sun will reach the surface of the Earth at the same time.

To solve the problem, we need to determine which electromagnetic (EM) wave from the visible spectrum reaches the Earth's surface first. The key points to consider are the properties of EM waves and their propagation through a vacuum. ### Step-by-Step Solution: 1. **Understanding EM Waves**: EM waves consist of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of propagation. The speed of EM waves in a vacuum is constant and is denoted by \( c \) (approximately \( 3 \times 10^8 \) m/s). 2. **Frequency and Wavelength Relationship**: The relationship between the speed \( c \), frequency \( \nu \), and wavelength \( \lambda \) of an EM wave is given by the equation: \[ ...
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