Light from a point source in air falls on a convex spherical glass surface `(mu = 1.5 and R = 20 cm)`. Calculate position of the image when the light source is at `1m` from the glass surface.
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Here, `mu_(1) = 1` (for air), `mu_(2) = 1.5` (for glass), `R = + 20 cm, u =-m = -100 cm, v = ?` As refraction occurs from rarer to denser medium, therefore `-(mu_(1))/(u) + (mu_(2))/(v) = (mu_(2) - mu_(1))/(R )` `-(1)/(-100) + (1.5)/(v) = (1.5 - 1)/(20) = (1)/(40)` `(3)/(2v) = (1)/(40) - (1)/(100) = (5 - 2)/(200) = (3)/(200)` `v = 100 cm` `:.` Image is formed at `100 cm` from the pole of the surface in the direction of incidence of light.
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(i) Device the mathematical n between refractive indices n_(1) and n_(2) of two radii and radius of curvature R for refraction at a convex shperical surface. Consider the object to be a point since lying on the principal axis in rarer medium of refractive index n_(1) and a real image formed in the denser medium of refractive index n_(2) . Hence, derive lens marker's formula. (ii) Light from a point source in air falls on a convex spherical glass surface of refractive index 1.5 and radius of curvature 20cm . The distance of light source from the glass surface is 100cm . At what position is the image formed ?
Light from a point source in air falls on a spherical glass surface mu = 1.5 and R = 20 cm . The image is formed at a distance of 100 cm from the glass surface in the direction of incident light. Calculate the object distance from the centre of curvature of the spherical surface.
Light from a point source in air falls on a spherical glass surface. If mu = 1.5 , and radius of curvature = 20 cm , the distance of light source from the glass surface is 100 cm , at what position will the image be formed ? (NCERT Solved Example)
Light from a point source in air falls on a spherical glass surface. If mu = 1.5 , and radius of curvature = 20 cm , the distance of light source from the glass surface is 100 cm , at what position will the image be formed ? (NCERT Solved Example)
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