Why the mass of the nucleus is less than the sum of masses of the nucleons?
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In the formation of the nucleus, the neutrons and protons have to collect in a very small space whos size of the order of `10^(-15)m`. The energy required for this purpose is spent by the nucleons at the cost of their masses. As a result of this, the mass of the nucleus formed becomes less than the sum of the masses of the individual nucleons.
The mass of an atomic nucleus is less than the sum of the masses of its constituents. Thus mass defect is converted in to
Which of the following statement (s) is/are correct (i) The rest mass of a stable nucleus is less than the sum of the rest masses of its separated nucleous (ii) The rest mass of a stable nucleus is greater than the sum of the rest masses of its separated nucleous (iii) In culear fusion, energy is released by fusion two nuclei of medium amss (approximaltely 100 "amu" ) (iv) In nuclear fussion, energy is released by freagmentation of a very heavy nucleus
The mass of a ._(3)^(7) Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ._(3)^(7)Li nucleus is nearly
The mass of a a_3^7 Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ._3^7 Li nucleus is nearly.
The mass number of a nucleus is
The mass of ._3^7Li is 0.042 amu less than the sum of masses of its constituents. The binding energy per nucleon is
PRADEEP-ATOMS AND NUCLEI-(I) Conceptual Problems 5
