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The diode shown in the circuit is a sili...

The diode shown in the circuit is a silicon diode. The potential difference between the points `A` and `B` will be

A

6V

B

0.6V

C

0.7V

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A

Here, diode is reverse biased, hence offer infinite resistance. Due to it, no current flows i.e. p-n junction acts as an open circuit in reverse biasing. The potential at `A` is equal to potential of negative electrode of `6 V` battery and potential of negative electrode of `6 V` battery and potential at `B` is equal to potential of positive electrode of `6V` battery. Thus pot. diff. between `A` and `B` is `6 V`.
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