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When the observer moves towards the stat...

When the observer moves towards the stationary source with velocity, `v_1`, the apparent frequency of emitted note is `f_1`. When the observer moves away from the source with velocity `v_1`, the apparent frequency is `f_2`. If v is the velocity of sound in air and `f_1/f_2` = 2,then `v/v_1` = ?

A

2

B

3

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
B
`F_(1)=(F[v+v_(1)])/(v),F_(2)(F[v-v_(2)])/(v)`
`(F_(1))/(F_(2))=(F[v+v_(1)])/(v)xx(v)/(F[v-v_(1)])`
`2=(v+v_(1))/(v-v_(1))`
`2v-2v_(1)=v_(1)+v`
`v=3v_(1)`
`(v)/(v_(1))=3`
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Knowledge Check

  • When the listener moves towards a stationary source with a velocity v_(1) m the apparent freqency of a note emitted by the source is f' When the listener moves away from the source with the same velocity, the apparent frequency of the note f/f'=3. If v the velocity of sound in air, the value of v//v_(1) is -

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