Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Maximum speed of the particle is `(g=10(m)/(s))`

Options

A. `2pi m//s`
B. `pi m//s`
C. `(1)/(2pi)m//s`
D. `(1)/(pi) m//s`

Answer

D

Explanation

`n= (1)/(2pi) sqrt((k)/(m))`
`25 =(1)/(4 pi^(2))k/m`
`k= 100pi^(2)m`
`K _(A) =mg A =(mg)/(k)`
`v _(max) =omegaA`
`=(2pi)/(T) A`
`=2pi n A`
`=(2pi 5xxmg)/(k)`
`v_(max) =(10pi xx10)/(100pi^(2))=(1)/(pi)`