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A current 0.5 ampere when passed through...

A current 0.5 ampere when passed through `AgNO_(3)` solution for 193 sec. Deposited 0.108 g of Ag. Find the equivalent weight of Ag.

A

108

B

54

C

10.8

D

5.4

Text Solution

Verified by Experts

The correct Answer is:
A

`W = ( I xx t(s) xx E)/(F)`
`therefore E = (W xx F)/(I xx t) = (0.108 xx 96500)/(0.5 xx 193) = 108`
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