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A current 0.5 ampere when passed through...

A current 0.5 ampere when passed through `AgNO_(3)` solution for 193 sec. Deposited 0.108 g of Ag. Find the equivalent weight of Ag.

A

108

B

54

C

10.8

D

5.4

Text Solution

Verified by Experts

The correct Answer is:
A
`W = ( I xx t(s) xx E)/(F)`
`therefore E = (W xx F)/(I xx t) = (0.108 xx 96500)/(0.5 xx 193) = 108`
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Knowledge Check

  • A current of 0.5 ampere when passed through AgNO_(3) solution for 193 seconds deposited 0.108 g of Ag. The equivalent weight of Ag is

    A
    10.8
    B
    108
    C
    54
    D
    1

  • A curent of 0.5 A when passed through AgNO_(3) solution for 193 s deposited 0.108 h Ag. The equivalent weight of silver is

    A
    108
    B
    54
    C
    10.8
    D
    5.4

  • 1.08 g of an element was displaced when a current of one ampere was passed through the solution of salt of the element for 16 minutes and five seconds. The equivalent weight of the element is

    A
    108
    B
    5.4
    C
    1.08
    D
    10.8

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