The density (in g `mL^(-1))` of a `3.60M` sulphuric acid solution that is `29% H_(2)SO_(4)` (Molar mass `= 98 g mol^(-1))` by mass will be

Options

A. (a)1.64
B. (b)1.88
C. (c )1.22
D. (d)1.45

Answer

C

Explanation

Let the density of solution be 'd'
Molarity of solution given `=3.6`
i.e., 1 litre of solution contains 3.6 moles of `H_(2)SO_(4)` or 1 litre of solution contains `3.6xx98 g` of `H_(2)SO_(4)` Since, the solution contains `29%` by mass.
`100 g` solution contains `29 g H_(2)SO_(4)`
`100/d mL` solution contains `29 g` of `H_(2)SO_(4)`
`1000 mL` solution contains `3.6xx98 g of H_(2)SO_(4)`
`:. 3.6xx98=(29xxd)/100xx1000`
`=1.22`