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The density (in g mL^(-1)) of a 3.60M su...

The density (in g `mL^(-1))` of a `3.60M` sulphuric acid solution that is `29% H_(2)SO_(4)` (Molar mass `= 98 g mol^(-1))` by mass will be

A

(a)1.64

B

(b)1.88

C

(c )1.22

D

(d)1.45

Text Solution

Verified by Experts

The correct Answer is:
C
Let the density of solution be 'd'
Molarity of solution given `=3.6`
i.e., 1 litre of solution contains 3.6 moles of `H_(2)SO_(4)` or 1 litre of solution contains `3.6xx98 g` of `H_(2)SO_(4)` Since, the solution contains `29%` by mass.
`100 g` solution contains `29 g H_(2)SO_(4)`
`100/d mL` solution contains `29 g` of `H_(2)SO_(4)`
`1000 mL` solution contains `3.6xx98 g of H_(2)SO_(4)`
`:. 3.6xx98=(29xxd)/100xx1000`
`=1.22`
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The density ( in g mL^(–1) ) of a 3.60 M sulphuric acid solution that is 29% H_(2)SO_(4) ( Molar mass = 98 "g mol"^(-1) ) by mass will be .......

Calculate the density ("in gm L"^(-1)) of a 3.60 M sulphuric acid solution that is 29 % H_(2)SO_(4) by mass ("molar mass = 98 g mol"^(-1))

Knowledge Check

  • The density ( in "g mL"^(-1) ) of a 3.60 M sulphuric acid solution that is 29% H_(2)SO_(4) (Molar mass = "98 g mol"^(-1) ) by mass will be

    A
    1.45
    B
    1.64
    C
    1.88
    D
    1.22

  • The density ( in g mL^(-1) ) of a 3.60 M sulphric acid solution that is 29 % H_(2) SO_(4) ( Molar mass = 98 g mol ^(-1) ) by mass will be _______.

    A
    `1.22`
    B
    `1.45`
    C
    `1.64`
    D
    `1.88`

  • The density (in g mL^(-1) ) of a 3.60 M sulphuric acid solution that is 29% H_2SO_4 (molar mass = 98 g mol^(-1) ) by mass, will be

    A
    1.45
    B
    1.64
    C
    1.88
    D
    1.22

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