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The molecules of a gas A travel four tim...

The molecules of a gas `A` travel four times faster than the molecules of gas `B` at same temperature. The ratio of molecular weights `(M_(A)//M_(B))` is

A

`1//16`

B

`4`

C

`1//4`

D

`16`

Text Solution

Verified by Experts

The correct Answer is:
A
`(r_(1))/(r_(2))=(x_(1))/(x_(2))=sqrt((M_(2))/(M_(1)))=4`
`(M_(2))/(M_(1))=16 (M_(1))/(M_(2))=(1)/(16)`
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Knowledge Check

  • When 4 g of an ideal gas A is introduced into an evacuated flask kept at 25^(@)C , the pressure is found to be one atmosphere. If 6 g of another ideal gas B is then added to the same flask, the pressure becomes 2 atm at same temperature. The ratio of molecular weights (M_(A) : M_(B)) of the two gases would be

    A
    `1:2`
    B
    `2:1`
    C
    `2:3`
    D
    `3:2`

  • The root mean square velocity of a gas molecule at any temperature T K of a gas molecule of molecular weight M is

    A
    `sqrt(8RT//M)`
    B
    `sqrt(2RT//M)`
    C
    `sqrt(3RT//M)`
    D
    zero

  • A molecule of gas is struck by another molecule of the same gas, the first molecule shows:

    A
    an exchange of potential energy
    B
    an exchange of kinetic energy
    C
    an exchange of chemical energy
    D
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