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Assertion: Ideal gas does not show Joule...

Assertion: Ideal gas does not show Joule-Thomson effect as well as they cannot be liquefied.
Reason: `((delE)/(delV))_(T)` and `((delT)/(delP))_(H)` for ideal gas is zero.

A

If both assertion and reason are true and the reason is the correct explanation of the assertion.

B

If both assertion and reason are true but reason is not the correct explanation of the assertion.

C

If assertion is true but reason is false.

D

If assertion is false but reason is true.

Text Solution

Verified by Experts

The correct Answer is:
A
Internal energy of an ideal gas depends only on temperature and since, they have no attractions among their molecules,
`((delT)/(delP))_(H)` is zero i.e., `mu_(jT)=0`
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Ideal gas do not show Joule -Thoson effect as well as they cannot be liquefied ((deltaU)/(deltaV))_(T)and ((deltaT)/(deltaP))_(H) for ideal gas is zero .

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Knowledge Check

  • ((delH)/(delP))_(T) for an ideal gas is equal to:

    A
    zero
    B
    `(DeltaVRT)/(P)`
    C
    `(PDeltaV)/(T)`
    D
    `nRDeltaT`

  • An ideal gas can't be liquefied because

    A
    its critical temperature is always above `0^(@)C`
    B
    its molecules are relatively smaller in size
    C
    it solidifies before becoming a liquid
    D
    forces operative between its molecules are negligible.

  • In case of an ideal gas, Joule Thomson effect is

    A
    zero
    B
    positive
    C
    negative
    D
    infinite

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