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When a solution of benzoic acid was titr...

When a solution of benzoic acid was titrated with `NaOH` the `pH` of the solution when half the acid neutralized was `4.2`. Dissociation constant of the acid is

A

`6.31xx10^(-5)`

B

`3.2xx10^(-5)`

C

`8.7xx10^(-8)`

D

`6.42xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
A

`underset(0.5)(C_(6)H_(5)COOH)+NaOHhArrunderset(0.5)(C_(6)H_(5)COONa)+H_(2)O`
After neutralization
It is a buffer solution of weak acid and its salt
`pH=pK_(a)+log``([sal t])/([acid])pK_(a)=4.2`
`K_(a)=6.31xx10^(-5)`
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Knowledge Check

  • The pH of 0.1 M acetic acid is 3, the dissociation constant of acid will be

    A
    `1.0 xx 10^(-4)`
    B
    `1.0 xx 10^(-5)`
    C
    `1.0 xx 10^(-3)`
    D
    `1.0 xx 10^(-8)`
  • The pH of a solution of hydrochloric acid is 4. The molarity of this solution is

    A
    `4.0`
    B
    `0.4`
    C
    `0.0001`
    D
    `0.04`
  • When a strong acid is titrated using a weak base, the pH at the equivalence point is

    A
    7
    B
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