Oxidation number of sulphur in `H_(2)SO_(5)` is

Options

A. `+2`
B. `+4`
C. `+8`
D. `+6`

Explanation

To find the oxidation number of sulfur in \( H_2SO_5 \), we can follow these steps:

### Step 1: Identify the components of the compound
The compound \( H_2SO_5 \) consists of hydrogen (H), sulfur (S), and oxygen (O). We need to determine the oxidation state of sulfur (S).

### Step 2: Assign oxidation numbers to known elements
- The oxidation number of hydrogen (H) is +1.
- The oxidation number of oxygen (O) in peroxides is -1, and in other compounds, it is typically -2. In \( H_2SO_5 \), we have two types of oxygen:
- 2 oxygen atoms are in the peroxide form (O-O), which will have an oxidation state of -1 each.
- The remaining 3 oxygen atoms will have an oxidation state of -2 each.

### Step 3: Set up the equation
Let the oxidation number of sulfur be \( X \). The total charge of the compound must equal zero. Therefore, we can set up the equation based on the oxidation numbers:

\[ 2(+1) + X + 3(-2) + 2(-1) = 0 \]

### Step 4: Simplify the equation
Now, let's simplify the equation:

\[ 2 + X - 6 - 2 = 0 \]

Combine like terms:

\[ X - 6 = 0 \]

### Step 5: Solve for \( X \)
Now, solve for \( X \):

\[ X = 6 \]

### Conclusion
The oxidation number of sulfur in \( H_2SO_5 \) is +6.

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