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When KMnO(4) is reduced with oxalic acid...

When `KMnO_(4)` is reduced with oxalic acid in acidic solution, the oxidation number of `Mn` changes from

A

`7` to `4`

B

`7` to `2`

C

`6` to `4`

D

`4` to `2`

Text Solution

Verified by Experts

The correct Answer is:
B
`5overset(COOH)underset(COOH)|+overset(+7)(2KMnO_(4))+3H_(2)SO_(4) rarr K_(2)SO_(4)+overset(+2)(2MnSO_(4))+10CO_(2)+8H_(2)O`
In this reaction oxidation state of `Mn` change from `+7` to `+2`.
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Knowledge Check

  • When KMnO_4 is reduced with .oxalic acid in acidic medium, the oxidation number of Mn changes from

    A
    `+7` to `+4`
    B
    `+6` to `+4`
    C
    `+7` to `+2`
    D
    `+4` to `+2`

  • In KMnO_4 oxidation number of Mn is

    A
    `2+`
    B
    `4+`
    C
    `6+`
    D
    `7+`

  • On reduction of KMnO_(4) by oxalic acid in acidic medium, the oxidation number of Mn changes.What is the magnitude of this change ?

    A
    From 7 to 2
    B
    From 6 to 2
    C
    From 5 to 2
    D
    From 7 to 4

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