Home
Class 11
CHEMISTRY
The oxidation number of sulphur in H(2)S...

The oxidation number of sulphur in `H_(2)S_(2)O_(7)` and iron in `K_(4)Fe(CN)_(6)` is respectively

A

`+6` and `+4`

B

`+2` and `+2`

C

`+8` and `+2`

D

`+6` and `+2`

Text Solution

Verified by Experts

The correct Answer is:
D

`H_(2)overset(*)(S_(2))O_(7)`
`2xx(+1)+2xx x+7xx(-2)=0`
`+2+2x-14=0`
`2x=14-2=12`
`x=(12)/(2)=+6` for `S`
`K_(4)overset(*)(F)e(CN)_(6)`
`4xx(+1)x+6xx(-1)=0`
`4+x-6=0`
`x=6-4=+2` for `Fe`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • REDOX REACTIONS

    A2Z|Exercise Balancing Of The Equation|28 Videos
  • REDOX REACTIONS

    A2Z|Exercise Stoichiometry In Redox Reactions|44 Videos
  • P BLOCK ELEMENTS ( Group 13 -14)

    A2Z|Exercise Section D - Chapter End Test|30 Videos
  • S BLOCK ELEMENTS ( GROUP 13 - 14)

    A2Z|Exercise Section D - Chapter End Test|29 Videos

Similar Questions

Explore conceptually related problems

EAN of iron in K_(4)[Fe(CN)_(6)] is

The oxidation state of sulphur in H_(2)S_(2)O_(7) is

Knowledge Check

  • The oxidation number of sulphur in H_(2)S_(2)O_(8) is:

    A
    `+2`
    B
    `+6`
    C
    `+7`
    D
    `+14`
  • The oxidation number of sulphur in Na_(2)S_(4)O_(6) is

    A
    `-2.5`
    B
    `+2.5`
    C
    `-10`
    D
    `+10`
  • The oxidation number of sulphur is Na_(2)S_(2)O_(4) is

    A
    `1.5`
    B
    `2.5`
    C
    3
    D
    2
  • Similar Questions

    Explore conceptually related problems

    The oxidation number of sulphur in Na_2S_4O_6 is .

    The oxidation state of sulphur in Na_(2)S_(4)O_(6) is

    The oxidation state of sulphur in Na_(2)S_(4)O_(6) is

    Oxidation number of S in H_(2)S_(2)O_(7) is -

    The oxidation number of sulphur in H_(2)SO_(4),H_(2)S_(2)O_(4) and H_(2)S_(2)O_(6) are respectively