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The plates of a parallel plate capacitor...

The plates of a parallel plate capacitor with no dielectirc are connected to a volatage source. Now a dielectric of dielectric constant `K` is inserted to fill the whose space between the plates with voltage source remainign connected to the capacitor-

A

the enegry stored in the capacitor

B

the electric field inside the capacitor will decrease to `K-` times

C

the force of attraction between the plates will increases to `K^(2)` times

D

the charge on the capacitor will increase to `K-` times

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
(A) `U_(i) = (1)/(2)CV^(2) & U_(f) = (1)/(2)(KC)V^(2)`
`U_(f) = KU_(i)`
(B) `E = (V)/(d) =` constant
(C ) Since charge on each plate increase to `k` times so force increase to `k^(2)` times
(D) `Q_(i) = CV & Q_(f) = (KC)V`
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