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Calculate the capacitance of a parallel ...

Calculate the capacitance of a parallel plate condenser of two plates `100cm xx 100cm` each separated by 2mm thick glass sheet of K = 4.

Text Solution

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Here, `A = 100 cm xx 100 cm = 10^(4) cm^(2) = 1m^(2), d = 2mm = 2xx10^(-3)m, K = 4, C = ?`
`C = (K in_(0) A)/(d) = (4xx8.85xx10^(-12)xx1)/(2xx10^(-3)) = 1.77xx10^(-8)` farad.
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Knowledge Check

  • The capacity of a parallel plate condenser consisting of two plates each 10 cm square and are seperated by a distance of 2 mm is (Take air as the medium between the plates).

    A
    `8.85 xx 10^(-13) F`
    B
    `4.42 xx 10^(-12) F`
    C
    `44.25 xx 10^(-12) F`
    D
    `88.5 xx 10^(-13) F`

  • A parallel plate condenser consists of two plates each of area 100cm^(2) . They are separated by mica sheet of thickness 8.85 mm. If the relative permittivity of mica is 6. Then capacity of parallel plate condenser is

    A
    50 pF
    B
    40 pF
    C
    60 pF
    D
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  • The capacitance of a parallel plate condenser with a separation of 4 mm between the plates is 7muF . If a mica sheet (K=6) of thickness 2 mm and of the same area is introduced betwenn the plates, its capacitance will be

    A
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    B
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    C
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    D
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