Find the equivalent capacitane between the points `P` and `Q` as shown in Fig. Given `C = 18 muF` and `C_(1) = 12 muF`

Answer

`11 muF`

Explanation

Equivalent capacitance between points `F` and `B` is
`= (18xx18)/(18+18) + 18 = 27 muF`
Equiavlent capacitance between `A` and `B`
`= 12 + (18xx27)/(18+27) = 22.8 = 23 muF`
Equivalent capacitance between `A` and `E`
`= (23xx18)/(23+18) + 18 = 28 muF`
Equivalent capacitance between `D` and `E`
`= (28xx18)/(28+18) + 12 = 23muF`
Equivalent capacitance between `D` and `Q`
`= (23xx18)/(23+18) + 18 = 28 muF`
Equivalent capacitance between `P` and `Q`
`= (28xx18)/(28+18) = 11 muF`