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Calculate the electric field in a copper...

Calculate the electric field in a copper wire of cross-sectional area 2.0 mm square carrying a current of 2 A. The resistivity of copper is `1.7 xx 10^(-8)Omega m`.

Text Solution

Verified by Experts

Here, `A=2.0 mm sq = 2xx2 mm^(2)`
`=4xx10^(6) m^(2)`,
`I= 2A , rho =1.7 xx 10^(-8) Omega m`.
Electric field `E=V/l = (IR)/(l) =(I rho l//A)/(l) = (l rho)/(A)`
`=(2xx(1.7 xx 10^(-8)))/(4xx10^(-6)) = 8.5 xx10^(-3) V//m`
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Calculate the electric field in a copper wire of cross-sectional area 2.0 mm^(2) carrying a current of 1 A. The resistivity of copper =1.7xx10^(-8) Omega m.

Calculate the electric field in a copper wire of cross-sectional area 2.0mm^(2) carrying a current of 1A .The resistivity of copper =1.7xx10^(-8)(Omega)m .

Knowledge Check

  • The electric field in the copper wire of area of cross - section 2mm^(2) carrying a current of 1A is (use resistivily of copper is 1.7 xx 10^(-8) Omegam)

    A
    `8.0 xx 10^(-2)Vm^(-1)`
    B
    `8.5 xx 10^(-2)V//m`
    C
    `8.0 xx 10^(-3)V//m`
    D
    `8.0 xx 10^(-4)V//m`

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