Calculate the electric field in a copper wire of cross-sectional area 2.0 mm square carrying a current of 2 A. The resistivity of copper is `1.7 xx 10^(-8)Omega m`.
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Here, `A=2.0 mm sq = 2xx2 mm^(2)` `=4xx10^(6) m^(2)`, `I= 2A , rho =1.7 xx 10^(-8) Omega m`. Electric field `E=V/l = (IR)/(l) =(I rho l//A)/(l) = (l rho)/(A)` `=(2xx(1.7 xx 10^(-8)))/(4xx10^(-6)) = 8.5 xx10^(-3) V//m`
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