What is the equivalent resistance between A and B in the net work of resistance .Find the correct through `12 Omega`

Explanation

Here `4 Omega` and `12 Omega` are in parallel. Their combined resistance `(4 xx 12)/(4 + 12) = 3 Omega` Similarly `6 Omega` and `3 Omega` are in parallel third combination resistance `= (3 xx 6)/(5 + 6) = 2 Omega`
Now the `3 Omega` resistance are in series so the equivalent resistance between `A` and `B = 3 + 2 = 5 Omega` current in the circuit `1 = (10V)/(5 Omega) = 2A`
potential difference across `12 Omega and 2 Omega = 2 xx 3 = 6V`
current though `12 Omega = (6)/(12) = (1)/(2)A`