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What fraction of the surface of a crysta...

What fraction of the surface of a crystal of `Cd at T = 298 K` consists of vacancies?
`Delta_("sub") H^(@) (Cd) = 113.02 kJ mol^(-1)` Energy needed in form a vacancy is appoximately 60% of `Delta _("sub") H^(0)`

A

`1.50 xx 10^(16)`

B

`6.02 xx 10^(-23)`

C

`6.02 xx 10^(22)`

D

`1.30 xx 10^(-12)`

Text Solution

Verified by Experts

The correct Answer is:
d
Fraction is expressed in terms of
`(n)/(N) = exp (-(E )/(KT))`
`E = 113.02 xx 10^(3) 1 mA^(-1) = (60)/(100)`
`R = 8.3143 JmA^(-1) K^(-1)`
`T = 298 K`
`(n)/(N) = ((113.02 xx 10^(3) xx 0.6)/(8.3143 xx 298))`
`= exp (- 27.369) - 1.30 + 10^(-12)`
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