Structure of a mixed oxide is cubic closed - packed (ccp) .The cubic unit cell of mixed oxide is composed of oxide ions .One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovelent metal B .The formula of the oxide is

Options

A. `ABO_(2)`
B. `A_(2)BO_(2)`
C. `A_(2)B_(3)O_(4)`
D. `AB_(2)O_(2)`

Answer

d

Explanation

we know, in ccp
If number of atoms` = n`
Then number of octabedral voids `= n`
and number of letrahedral voids `= 2n`
` :. {:(A^(2+),B^(+),O^(2-)),(n'2'1/4,n,n),(n/1,n,n),(1,2,2):}`