Home
Class 12
CHEMISTRY
Equivalent weight of KMnO(4) acting as a...

Equivalent weight of `KMnO_(4)` acting as an oxidant in acidic medium is

A

Molecular weight of `KMnO_(4)`

B

`(1)/(2) xx` Molecular weight of `KMnO_(4)`

C

`(1)/(3) xx` Molecular weight of `KMnO_(4)`

D

`(1)/(5) xx` Molecular weight of `KNnO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(1)/(5) xx` molecular weight of `KMnO_(4)`
as transfer of `5 e^(-)` takes place when `KMnO_(4)` acts as oxidant in acidic medium.
`2KMn_(4) + 3H_(2) SO_(4) rarr K_(2)SO_(4) + 2MNSO_(4) - 3H_(2)O + 50`
Promotional Banner

Topper's Solved these Questions

  • THE D AND F BLOCK ELEMENTS

    A2Z|Exercise KMnO_4 And K_2Cr_2O_51|1 Videos

  • THE D AND F BLOCK ELEMENTS

    A2Z|Exercise KMnO_4 And K_2Cr_2O_52|1 Videos

  • THE D AND F BLOCK ELEMENTS

    A2Z|Exercise KMnO_4 And K_2Cr_2O_49|1 Videos

  • SURFACE CHEMISTRY

    A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

The equivalent weight of KMnO_(4) in (a) neutral medium, (b) acidic medium and (c ) alkaline medium is M//.. ( where M is mol.wt. of KMnO_(4) )

The equivalent weight of KMnO_4 in a redox reaction in a neutral medium is .

KMnO_(4) reacts with KI in acidic medium gives

A : Equivalent weight of KMnO_(4) in acidic medium is M/5 . R : In acidic medium 1 mol of MnO_(4)""^(-) gains 5 electron.

STATEMENT-1 KMnO_(4) acts as powerful oxidising agent in acids, alkaline and neutral medium. STATEMENT-2: Equivalent weight of KMnO_(4) in acidic medium in M/5 and in strongly alkaline medium in M/3. STATEMENT-3 : KMnO_(4) solution is used as a primary standard and acts as self indicator during its titration more Mohr salt.

Assertion :- Equivalent weight of KMnO_(4) in acidic medium is M//5 (M=molecular weight) while in basic medium, it is equal of M/3. Reason :- In acidic medium, 1 mol of MnO_(4)^(-) gains 5 mole electrons while in basic medium it gains 3 mole electrons.

Knowledge Check

  • The equivalent weights of KMnO_(4) as an oxidising agent in acidic and neutral media will be respectively (M = molecular weight of KMnO_(4) )

    A
    M/7 and M/2
    B
    M/5 and M/3
    C
    M/4 and M/5
    D
    M/2 and M/4

  • Equivalent weight of KMnO_4 in acidic medium is

    A
    M/2
    B
    M/4
    C
    M/7
    D
    M/5

  • Equivalent weight of KMnO_4 in acidic medium is

    A
    M/2
    B
    M/4
    C
    M/7
    D
    M/5