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Equivalent weight of KMnO(4) acting as a...

Equivalent weight of `KMnO_(4)` acting as an oxidant in acidic medium is

A

Molecular weight of `KMnO_(4)`

B

`(1)/(2) xx` Molecular weight of `KMnO_(4)`

C

`(1)/(3) xx` Molecular weight of `KMnO_(4)`

D

`(1)/(5) xx` Molecular weight of `KNnO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(1)/(5) xx` molecular weight of `KMnO_(4)`
as transfer of `5 e^(-)` takes place when `KMnO_(4)` acts as oxidant in acidic medium.
`2KMn_(4) + 3H_(2) SO_(4) rarr K_(2)SO_(4) + 2MNSO_(4) - 3H_(2)O + 50`
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The equivalent weight of KMnO_(4) in (a) neutral medium, (b) acidic medium and (c ) alkaline medium is M//.. ( where M is mol.wt. of KMnO_(4) )

The equivalent weight of KMnO_4 in a redox reaction in a neutral medium is .

Knowledge Check

  • The equivalent weights of KMnO_(4) as an oxidising agent in acidic and neutral media will be respectively (M = molecular weight of KMnO_(4) )

    A
    M/7 and M/2
    B
    M/5 and M/3
    C
    M/4 and M/5
    D
    M/2 and M/4

  • Equivalent weight of KMnO_4 in acidic medium is

    A
    M/2
    B
    M/4
    C
    M/7
    D
    M/5

  • Equivalent weight of KMnO_4 in acidic medium is

    A
    M/2
    B
    M/4
    C
    M/7
    D
    M/5

    • Similar Questions

    Explore conceptually related problems

    KMnO_(4) reacts with KI in acidic medium gives

    If molecular weight of KMnO_(4) is M then its equivalent weight in acidic medium would be

    A : Equivalent weight of KMnO_(4) in acidic medium is M/5 . R : In acidic medium 1 mol of MnO_(4)""^(-) gains 5 electron.

    STATEMENT-1 KMnO_(4) acts as powerful oxidising agent in acids, alkaline and neutral medium. STATEMENT-2: Equivalent weight of KMnO_(4) in acidic medium in M/5 and in strongly alkaline medium in M/3. STATEMENT-3 : KMnO_(4) solution is used as a primary standard and acts as self indicator during its titration more Mohr salt.

    Assertion :- Equivalent weight of KMnO_(4) in acidic medium is M//5 (M=molecular weight) while in basic medium, it is equal of M/3. Reason :- In acidic medium, 1 mol of MnO_(4)^(-) gains 5 mole electrons while in basic medium it gains 3 mole electrons.

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