Potassium permanganate works as oxidising agent both in acidic and basic medium. In bot state product obtained by `KMnO_(4)` is respectively

Options

A. `MnO_(2)^(-)` and `Mn^(3+)`
B. `Mn^(3+)` and `Mn^(2+)`
C. `Mn^(2+)` and `MnO_(2)`
D. `MnO_(2)` and `Mn^(2+)`

Answer

D

Explanation

In alkaline medium, `KMnO_(4)` first reduced in manganate and then in insoluble manganese dioxide
`2MnO_(4)^(-) + H_(2) O rarr 2MnO_(2) + 2 OH^(-) + 3 [O]`
In acidic medium, manganous sulphate formed
`MnO_(3)^(-) + 8H^(+) + 5 e^(-) rarr Mn^(2+) + 4H_(2) O`.