`[Co(NH_3)_5Br]SO_4` and `[CO(NH_3)_5SO_4]Br` are examples of which type of isomerism

Options

A. (a) Linkage
B. (b) Geometrical
C. (c) Ionization
D. (d) Optical

Explanation

To determine the type of isomerism exhibited by the coordination compounds `[Co(NH_3)_5Br]SO_4` and `[Co(NH_3)_5SO_4]Br`, we can follow these steps:

### Step 1: Identify the Components of Each Compound
- The first compound is `[Co(NH_3)_5Br]SO_4`, which consists of a cobalt ion coordinated with five ammonia (NH₃) ligands and one bromide (Br) ligand, with a sulfate (SO₄) counterion.
- The second compound is `[Co(NH_3)_5SO_4]Br`, which has the same cobalt ion coordinated with five ammonia ligands and one sulfate ligand, with a bromide counterion.

### Step 2: Analyze the Position of Ligands
- In the first compound, the bromide ion is part of the coordination sphere (inside the brackets), while the sulfate ion is outside the coordination sphere.
- In the second compound, the sulfate ion is part of the coordination sphere, while the bromide ion is outside.

### Step 3: Understand the Concept of Ionization Isomerism
- Ionization isomerism occurs when two or more coordination compounds have the same formula but differ in the position of the ligands inside and outside the coordination sphere, leading to different ions when dissolved in solution.
- In this case, when `[Co(NH_3)_5Br]SO_4` is dissolved, it produces `[Co(NH_3)_5Br]²⁺` and `SO₄²⁻`.
- When `[Co(NH_3)_5SO_4]Br` is dissolved, it produces `[Co(NH_3)_5SO₄]²⁺` and `Br⁻`.

### Step 4: Conclude the Type of Isomerism
- Since the two compounds produce different ions upon dissolution due to the different positions of the ligands, they are classified as **ionization isomers**.

### Final Answer
The compounds `[Co(NH_3)_5Br]SO_4` and `[Co(NH_3)_5SO_4]Br` are examples of **ionization isomerism**.

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