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The oxidation number of Cr in [Cr(NH3)6]...

The oxidation number of `Cr` in `[Cr(NH_3)_6]Cl_3` is

A

(a) `8`

B

(b) `6`

C

(c) `4`

D

(d) `3`

Text Solution

Verified by Experts

The correct Answer is:
D
`x+6xx(0)+3xx(-1)=0`
`x-3=0`, `x=+3`. Oxidation number of `Cr` is `=+3`
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