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Considering H2O as a weak field ligand, ...

Considering `H_2O` as a weak field ligand, the number of unpaired electrons in `[Mn(H_2O)_6]^(2+)` will be (At. no. of `Mn=25`)

A

(a) Two

B

(b) Four

C

(c) Three

D

(d) Five

Text Solution

Verified by Experts

The correct Answer is:
D

In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons `=5`.
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