The rate constatnt of a second order reaction is ` 10^(-2) "mol"^(-1)` litre `sec^(-1)`. The rate constant when expressedd in ` cm^(3)" molecule"^(-1) "min"^(-1)` is :

Options

A. ` 9.96 xx 10-^(22)`
B. ` 9. 96 xx 10^(23)`
C. ` 9.96 xx 10^(21)`
D. ` 1.004 xx 10^(-24)`

Answer

A

Explanation

`K=10^(-2) "mol"^(-1)" litre "sec^(-1)`
`=(10^(-2)xx1000xx60)/(6.02xx10^(22))c c "molecule"^(-1) "min"^(-1)`.
`=9.9618xx10^(-22) cc "molecule"^(-1) "minm"^(-1)`